# Line slope calculator 4x+9y=90

**Straight line given by points A[0; 10] and B[9; 6]**

## Calculation:

**Slope-intercept form of line:**y = -0.4444x+10

**Canonical form of the line equation:**4x+9y-90 = 0

**Parametric form of the line equation:**

x = 9t

y = -4t+10 ; t ∈ R

**Slope:**m = -0.4444

**Slope angle of line: φ =**-23°57'45″ = -0.4182 rad

**X intercept:**x

_{0}= 22.5

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 9.1381

**The length of the segment AB: |AB| =**9.8489

**Vector: AB =**(9; -4)

**Normal vector: n =**(4; 9)

**Midpoint of the segment AB: M =**[4.5; 8]

**Perpendicular Bisector equation:**9x-4y-8.5 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (9; 6) ; |OB| = 10.8167**

**Scalar product OA .OB = 60**

**Angle ∠ AOB = 56°18'36″ = 0.9828 rad**